Optimal. Leaf size=301 \[ \frac {2 B n \text {Li}_2\left (\frac {(d g-c h) (a+b x)}{(b g-a h) (c+d x)}\right ) \left (B \log \left (e (a+b x)^n (c+d x)^{-n}\right )+A\right )}{h}+\frac {\log \left (1-\frac {(a+b x) (d g-c h)}{(c+d x) (b g-a h)}\right ) \left (B \log \left (e (a+b x)^n (c+d x)^{-n}\right )+A\right )^2}{h}-\frac {2 B n \text {Li}_2\left (\frac {d (a+b x)}{b (c+d x)}\right ) \left (B \log \left (e (a+b x)^n (c+d x)^{-n}\right )+A\right )}{h}-\frac {\log \left (\frac {b c-a d}{b (c+d x)}\right ) \left (B \log \left (e (a+b x)^n (c+d x)^{-n}\right )+A\right )^2}{h}-\frac {2 B^2 n^2 \text {Li}_3\left (\frac {(d g-c h) (a+b x)}{(b g-a h) (c+d x)}\right )}{h}+\frac {2 B^2 n^2 \text {Li}_3\left (\frac {d (a+b x)}{b (c+d x)}\right )}{h} \]
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Rubi [A] time = 0.82, antiderivative size = 473, normalized size of antiderivative = 1.57, number of steps used = 16, number of rules used = 10, integrand size = 33, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.303, Rules used = {6742, 2494, 2394, 2393, 2391, 2489, 2488, 2506, 6610, 2503} \[ -\frac {2 A B n \text {PolyLog}\left (2,\frac {b (g+h x)}{b g-a h}\right )}{h}+\frac {2 B^2 n \log \left (e (a+b x)^n (c+d x)^{-n}\right ) \text {PolyLog}\left (2,1-\frac {(g+h x) (b c-a d)}{(c+d x) (b g-a h)}\right )}{h}-\frac {2 B^2 n \text {PolyLog}\left (2,1-\frac {b c-a d}{b (c+d x)}\right ) \log \left (e (a+b x)^n (c+d x)^{-n}\right )}{h}-\frac {2 B^2 n^2 \text {PolyLog}\left (3,1-\frac {(g+h x) (b c-a d)}{(c+d x) (b g-a h)}\right )}{h}+\frac {2 B^2 n^2 \text {PolyLog}\left (3,1-\frac {b c-a d}{b (c+d x)}\right )}{h}+\frac {2 A B n \text {PolyLog}\left (2,\frac {d (g+h x)}{d g-c h}\right )}{h}+\frac {2 A B \log (g+h x) \log \left (e (a+b x)^n (c+d x)^{-n}\right )}{h}-\frac {2 A B n \log (g+h x) \log \left (-\frac {h (a+b x)}{b g-a h}\right )}{h}+\frac {B^2 \log ^2\left (e (a+b x)^n (c+d x)^{-n}\right ) \log \left (\frac {(g+h x) (b c-a d)}{(c+d x) (b g-a h)}\right )}{h}-\frac {B^2 \log \left (\frac {b c-a d}{b (c+d x)}\right ) \log ^2\left (e (a+b x)^n (c+d x)^{-n}\right )}{h}+\frac {A^2 \log (g+h x)}{h}+\frac {2 A B n \log (g+h x) \log \left (-\frac {h (c+d x)}{d g-c h}\right )}{h} \]
Antiderivative was successfully verified.
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Rule 2391
Rule 2393
Rule 2394
Rule 2488
Rule 2489
Rule 2494
Rule 2503
Rule 2506
Rule 6610
Rule 6742
Rubi steps
\begin {align*} \int \frac {\left (A+B \log \left (e (a+b x)^n (c+d x)^{-n}\right )\right )^2}{g+h x} \, dx &=\int \left (\frac {A^2}{g+h x}+\frac {2 A B \log \left (e (a+b x)^n (c+d x)^{-n}\right )}{g+h x}+\frac {B^2 \log ^2\left (e (a+b x)^n (c+d x)^{-n}\right )}{g+h x}\right ) \, dx\\ &=\frac {A^2 \log (g+h x)}{h}+(2 A B) \int \frac {\log \left (e (a+b x)^n (c+d x)^{-n}\right )}{g+h x} \, dx+B^2 \int \frac {\log ^2\left (e (a+b x)^n (c+d x)^{-n}\right )}{g+h x} \, dx\\ &=\frac {A^2 \log (g+h x)}{h}+\frac {2 A B \log \left (e (a+b x)^n (c+d x)^{-n}\right ) \log (g+h x)}{h}+\frac {\left (B^2 d\right ) \int \frac {\log ^2\left (e (a+b x)^n (c+d x)^{-n}\right )}{c+d x} \, dx}{h}-\frac {\left (B^2 (d g-c h)\right ) \int \frac {\log ^2\left (e (a+b x)^n (c+d x)^{-n}\right )}{(c+d x) (g+h x)} \, dx}{h}-\frac {(2 A b B n) \int \frac {\log (g+h x)}{a+b x} \, dx}{h}+\frac {(2 A B d n) \int \frac {\log (g+h x)}{c+d x} \, dx}{h}\\ &=-\frac {B^2 \log \left (\frac {b c-a d}{b (c+d x)}\right ) \log ^2\left (e (a+b x)^n (c+d x)^{-n}\right )}{h}+\frac {A^2 \log (g+h x)}{h}-\frac {2 A B n \log \left (-\frac {h (a+b x)}{b g-a h}\right ) \log (g+h x)}{h}+\frac {2 A B n \log \left (-\frac {h (c+d x)}{d g-c h}\right ) \log (g+h x)}{h}+\frac {2 A B \log \left (e (a+b x)^n (c+d x)^{-n}\right ) \log (g+h x)}{h}+\frac {B^2 \log ^2\left (e (a+b x)^n (c+d x)^{-n}\right ) \log \left (\frac {(b c-a d) (g+h x)}{(b g-a h) (c+d x)}\right )}{h}+(2 A B n) \int \frac {\log \left (\frac {h (a+b x)}{-b g+a h}\right )}{g+h x} \, dx-(2 A B n) \int \frac {\log \left (\frac {h (c+d x)}{-d g+c h}\right )}{g+h x} \, dx+\frac {\left (2 B^2 (b c-a d) n\right ) \int \frac {\log \left (-\frac {-b c+a d}{b (c+d x)}\right ) \log \left (e (a+b x)^n (c+d x)^{-n}\right )}{(a+b x) (c+d x)} \, dx}{h}-\frac {\left (2 B^2 (b c-a d) n\right ) \int \frac {\log \left (e (a+b x)^n (c+d x)^{-n}\right ) \log \left (-\frac {(-b c+a d) (g+h x)}{(b g-a h) (c+d x)}\right )}{(a+b x) (c+d x)} \, dx}{h}\\ &=-\frac {B^2 \log \left (\frac {b c-a d}{b (c+d x)}\right ) \log ^2\left (e (a+b x)^n (c+d x)^{-n}\right )}{h}+\frac {A^2 \log (g+h x)}{h}-\frac {2 A B n \log \left (-\frac {h (a+b x)}{b g-a h}\right ) \log (g+h x)}{h}+\frac {2 A B n \log \left (-\frac {h (c+d x)}{d g-c h}\right ) \log (g+h x)}{h}+\frac {2 A B \log \left (e (a+b x)^n (c+d x)^{-n}\right ) \log (g+h x)}{h}+\frac {B^2 \log ^2\left (e (a+b x)^n (c+d x)^{-n}\right ) \log \left (\frac {(b c-a d) (g+h x)}{(b g-a h) (c+d x)}\right )}{h}-\frac {2 B^2 n \log \left (e (a+b x)^n (c+d x)^{-n}\right ) \text {Li}_2\left (1-\frac {b c-a d}{b (c+d x)}\right )}{h}+\frac {2 B^2 n \log \left (e (a+b x)^n (c+d x)^{-n}\right ) \text {Li}_2\left (1-\frac {(b c-a d) (g+h x)}{(b g-a h) (c+d x)}\right )}{h}+\frac {(2 A B n) \operatorname {Subst}\left (\int \frac {\log \left (1+\frac {b x}{-b g+a h}\right )}{x} \, dx,x,g+h x\right )}{h}-\frac {(2 A B n) \operatorname {Subst}\left (\int \frac {\log \left (1+\frac {d x}{-d g+c h}\right )}{x} \, dx,x,g+h x\right )}{h}+\frac {\left (2 B^2 (b c-a d) n^2\right ) \int \frac {\text {Li}_2\left (1+\frac {-b c+a d}{b (c+d x)}\right )}{(a+b x) (c+d x)} \, dx}{h}-\frac {\left (2 B^2 (b c-a d) n^2\right ) \int \frac {\text {Li}_2\left (1+\frac {(-b c+a d) (g+h x)}{(b g-a h) (c+d x)}\right )}{(a+b x) (c+d x)} \, dx}{h}\\ &=-\frac {B^2 \log \left (\frac {b c-a d}{b (c+d x)}\right ) \log ^2\left (e (a+b x)^n (c+d x)^{-n}\right )}{h}+\frac {A^2 \log (g+h x)}{h}-\frac {2 A B n \log \left (-\frac {h (a+b x)}{b g-a h}\right ) \log (g+h x)}{h}+\frac {2 A B n \log \left (-\frac {h (c+d x)}{d g-c h}\right ) \log (g+h x)}{h}+\frac {2 A B \log \left (e (a+b x)^n (c+d x)^{-n}\right ) \log (g+h x)}{h}+\frac {B^2 \log ^2\left (e (a+b x)^n (c+d x)^{-n}\right ) \log \left (\frac {(b c-a d) (g+h x)}{(b g-a h) (c+d x)}\right )}{h}-\frac {2 A B n \text {Li}_2\left (\frac {b (g+h x)}{b g-a h}\right )}{h}+\frac {2 A B n \text {Li}_2\left (\frac {d (g+h x)}{d g-c h}\right )}{h}-\frac {2 B^2 n \log \left (e (a+b x)^n (c+d x)^{-n}\right ) \text {Li}_2\left (1-\frac {b c-a d}{b (c+d x)}\right )}{h}+\frac {2 B^2 n \log \left (e (a+b x)^n (c+d x)^{-n}\right ) \text {Li}_2\left (1-\frac {(b c-a d) (g+h x)}{(b g-a h) (c+d x)}\right )}{h}+\frac {2 B^2 n^2 \text {Li}_3\left (1-\frac {b c-a d}{b (c+d x)}\right )}{h}-\frac {2 B^2 n^2 \text {Li}_3\left (1-\frac {(b c-a d) (g+h x)}{(b g-a h) (c+d x)}\right )}{h}\\ \end {align*}
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Mathematica [B] time = 0.49, size = 1082, normalized size = 3.59 \[ \frac {-2 n \left (-n \log (a+b x)+n \log (c+d x)+\log \left (e (a+b x)^n (c+d x)^{-n}\right )\right ) \left (\log (c+d x) \log \left (\frac {d (g+h x)}{d g-c h}\right )+\text {Li}_2\left (\frac {h (c+d x)}{c h-d g}\right )\right ) B^2+n^2 \left (\log \left (\frac {b (g+h x)}{b g-a h}\right ) \log ^2(a+b x)+2 \text {Li}_2\left (\frac {h (a+b x)}{a h-b g}\right ) \log (a+b x)-2 \text {Li}_3\left (\frac {h (a+b x)}{a h-b g}\right )\right ) B^2+n^2 \left (\log \left (\frac {d (g+h x)}{d g-c h}\right ) \log ^2(c+d x)+2 \text {Li}_2\left (\frac {h (c+d x)}{c h-d g}\right ) \log (c+d x)-2 \text {Li}_3\left (\frac {h (c+d x)}{c h-d g}\right )\right ) B^2-2 n^2 \left (\frac {1}{2} \left (\log \left (\frac {a d-b c}{d (a+b x)}\right )+\log \left (\frac {b (g+h x)}{b g-a h}\right )-\log \left (\frac {(a d-b c) (g+h x)}{(d g-c h) (a+b x)}\right )\right ) \log ^2\left (\frac {(b g-a h) (c+d x)}{(d g-c h) (a+b x)}\right )+\log \left (\frac {h (c+d x)}{c h-d g}\right ) \left (\log \left (\frac {d (g+h x)}{d g-c h}\right )-\log \left (\frac {b (g+h x)}{b g-a h}\right )\right ) \log \left (\frac {(b g-a h) (c+d x)}{(d g-c h) (a+b x)}\right )+\left (\text {Li}_2\left (\frac {b (c+d x)}{d (a+b x)}\right )-\text {Li}_2\left (\frac {(b g-a h) (c+d x)}{(d g-c h) (a+b x)}\right )\right ) \log \left (\frac {(b g-a h) (c+d x)}{(d g-c h) (a+b x)}\right )+\log (a+b x) \log (c+d x) \log \left (\frac {b (g+h x)}{b g-a h}\right )+\frac {1}{2} \log \left (\frac {h (c+d x)}{c h-d g}\right ) \left (\log \left (\frac {h (c+d x)}{c h-d g}\right )-2 \log (a+b x)\right ) \left (\log \left (\frac {b (g+h x)}{b g-a h}\right )-\log \left (\frac {d (g+h x)}{d g-c h}\right )\right )+\left (\log (c+d x)-\log \left (\frac {(b g-a h) (c+d x)}{(d g-c h) (a+b x)}\right )\right ) \text {Li}_2\left (\frac {h (a+b x)}{a h-b g}\right )+\left (\log (a+b x)+\log \left (\frac {(b g-a h) (c+d x)}{(d g-c h) (a+b x)}\right )\right ) \text {Li}_2\left (\frac {h (c+d x)}{c h-d g}\right )-\text {Li}_3\left (\frac {h (a+b x)}{a h-b g}\right )-\text {Li}_3\left (\frac {h (c+d x)}{c h-d g}\right )-\text {Li}_3\left (\frac {b (c+d x)}{d (a+b x)}\right )+\text {Li}_3\left (\frac {(b g-a h) (c+d x)}{(d g-c h) (a+b x)}\right )\right ) B^2+2 n \left (A+B \left (-n \log (a+b x)+n \log (c+d x)+\log \left (e (a+b x)^n (c+d x)^{-n}\right )\right )\right ) \left (\log (a+b x) \log \left (\frac {b (g+h x)}{b g-a h}\right )+\text {Li}_2\left (\frac {h (a+b x)}{a h-b g}\right )\right ) B-2 A n \left (\log (c+d x) \log \left (\frac {d (g+h x)}{d g-c h}\right )+\text {Li}_2\left (\frac {h (c+d x)}{c h-d g}\right )\right ) B+\left (A+B \left (-n \log (a+b x)+n \log (c+d x)+\log \left (e (a+b x)^n (c+d x)^{-n}\right )\right )\right )^2 \log (g+h x)}{h} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.87, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {B^{2} \log \left (\frac {{\left (b x + a\right )}^{n} e}{{\left (d x + c\right )}^{n}}\right )^{2} + 2 \, A B \log \left (\frac {{\left (b x + a\right )}^{n} e}{{\left (d x + c\right )}^{n}}\right ) + A^{2}}{h x + g}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (B \log \left (\frac {{\left (b x + a\right )}^{n} e}{{\left (d x + c\right )}^{n}}\right ) + A\right )}^{2}}{h x + g}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 2.63, size = 0, normalized size = 0.00 \[ \int \frac {\left (B \ln \left (e \left (b x +a \right )^{n} \left (d x +c \right )^{-n}\right )+A \right )^{2}}{h x +g}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {A^{2} \log \left (h x + g\right )}{h} + \int \frac {B^{2} \log \left ({\left (b x + a\right )}^{n}\right )^{2} + B^{2} \log \left ({\left (d x + c\right )}^{n}\right )^{2} + B^{2} \log \relax (e)^{2} + 2 \, A B \log \relax (e) + 2 \, {\left (B^{2} \log \relax (e) + A B\right )} \log \left ({\left (b x + a\right )}^{n}\right ) - 2 \, {\left (B^{2} \log \left ({\left (b x + a\right )}^{n}\right ) + B^{2} \log \relax (e) + A B\right )} \log \left ({\left (d x + c\right )}^{n}\right )}{h x + g}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (A+B\,\ln \left (\frac {e\,{\left (a+b\,x\right )}^n}{{\left (c+d\,x\right )}^n}\right )\right )}^2}{g+h\,x} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: HeuristicGCDFailed} \]
Verification of antiderivative is not currently implemented for this CAS.
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